Match the following aqueous solutions with the appropriate letter from the column on the right.
1. | 0.15 m | MgCl2 | A. | Highest boiling point | ||
2. | 0.16 m | (NH4)2CO3 | B. | Second highest boiling point | ||
3. | 0.13 m | CoBr2 | C. | Third highest boiling point | ||
4. | 0.42 m | Glucose(nonelectrolyte) | D. | Lowest boiling point |
answer :
A ) Highest boiling point -------------------> (NH4)2CO3
B) Second highest boiling point ----------------> MgCl2
C ) Third highest boiling point --------------> glucose
D ) Lowest boiling point -------------------->CoBr2
explanation:
1 ) for MgCl2 = i x m = 3 x 0.15 = 0.45 m
2) for (NH4)2CO3 = i x m = 3 x 0.16 = 0.48 m
3) for CoBr2 = i x m = 3 x 0.13 = 0.39 m
4 ) glucose = i x m = 1 x 0.42 m
here i = number of ions . more value more boiling point from the formula :
delta Tf = kf x i x m
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