Question

The reaction A(g)⇌2B(g) has an equilibrium constant of K = 0.010. What is the equilibrium constant for the reaction B(g)⇌12A(g)?

Express your answer using two significant figures.

Answer 1

I think question is wrong. One time chek it.

Question shoild be like this

The reaction A(g)⇌2B(g) has an equilibrium constant of K = 0.010. What is the equilibrium constant for the reaction B(g)⇌(1/2)A(g)?

Answer for above question

First reaction

A(g) ⇌ 2B(g) K = 0.010

K = [B]²/[A] = 0.010 ===> [A] = [B]² /0.010 ------> (1)

Second reaction

B(g) ⇌ (1/2)A(g)

K = [A]^(1/2)/[B]

Substitute [A] = [B]²/0.010 value in top K equation

K = [A]^(1/2)/[B] = ([B]²/0.010)^(1/2)x[B] = (1/0.010)^(1/2) = 10