For the reaction shown above, what is the chemical formula for the limiting reactant?
Chemical equation: 4Cr (s) +3O2 (g) ----> 2Cr2O3 (s)
The balanced equation above states that 4 moles of Cr react with 3
moles of O2 to produce 2 moles of Cr2O3
So, 1 mole of Cr needs 0.75 moles of O2.
If the mole ratio of Cr : O2 is not 1 : 1.333, then you have an
excess of one reagent. The other reagent is the limiting
reagent.
Set up a proportion to determine the amount of O2 needed.
The dots are to prevent yahoo answers from scrunching the letters
and numbers to the left!!
.. (moles of Cr)
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