Question

Given the concentration of CO₂ in the atmosphere is 407 ppm (= 0.000407 mol fraction), determine the equilibrium concentration of CO₂ in water, [CO₂] at 10°C in mol/L

Answer 1

mole fraction of CO2 in air = 0.000407 (407 ppm)

molefraction of CO2 in water = 1 - 0.000407 = 0.000593

Concentration of CO2 = 593 ppm

1 ppm means 1g of solute in 10^6 g of solution.

so we can write it as 0.001 g in 10^3 g of solution

so 1 mg of solute in 1000g of solution

if you take aqueous solutions then it will become

1mg in 1000mL of solution

we have 593 ppm of CO2

then 593 mg of CO2 in 1L of solution

Concentration of CO2 in water = (593 * 10^-3 /18) *1/1

Concentration of CO2 = 32.94 *10^-3 = 0.03294 mol/L