Question

How many mL of .452M H3PO4 solution are required to react completely with 75.0 mL of...

How many mL of .452M H3PO4 solution are required to react completely with 75.0 mL of 0.205 M NaOH solution?

Homework Answers

Answer #1

H3PO4 + 3NaOH -----------> Na3PO4 + 3H2O

According to the above balanced equation, 3 moles of NaOH is required to react completely with 1 mole of H3PO4.

No.of moles of NaOH = conc. x volume = 0.205 x (75/1000) = 0.0154 moles

No.of moles of H3PO4 = (1/3) no.of moles of NaOH = 0.0154 / 3 = 5.1 x 10-3 moles

No.of moles of H3PO4 = conc. x volume

=> 5.1 x 10^-3 = 0.452 x volume

=> volume = 0.01128 L

=> volume = 11.28 mL <<<<<<<--------------(ANSWER)

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