Question

Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O . Suppose 23.7 g of hydrochloric acid is mixed with 40. g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits.

Answer 1

reaction is

HCl + NaOH = NaCl + H2O

first we have to calculate the moles of HCl and NaOH so from this we can find the limiting reagent in this reaction

now moles of HCl = weight of HCl/ molecular weight of HCl

= 23.7/36.5 = 0.6493

similiarly moles of NaOH = weight of NaOH/molecular weight of NaOH

= 40/40 = 1 moles

so now in this reaction limiting rewagent is HCl (0.6493 moles) reacted with 1 mole of NaOH

thearticall yield of any reaction is = molecular weight of anticipated product x weight of limiting reagent/molecular weight of limiting reagent

now weight of can be produced in this reaction is = 18 x23.7/36.5

= 11.68 gm