For the following reaction at equilibrium, which change would shift the position of equilibrium toward forming more products? (Select your answer(s) as there may be more than one.)2NOBr(g) 2NO(g) + Br2(g), ∆Hºrxn = +30 kJ/mol
A)Decrease the total pressure by increasing the volume.
B)Add NO.
C)Remove Br2.
D)Raise the temperature.
E)Add NOBr
Kc for the reaction is =[NO]2 [Br2]/ [NOBr]2
When NO is added, numeratorr increases and to keep the equilibrium constant same, NoBr also increases and hence backward reaction is favored.
when Br2 is removed, numerator decreases Hence denominator also decreases. So more products are formed,
The given reaction is endothermic, increasing the temperature takes the reaction towards the endothermic direction. Hence more products are formed.
when NoBr is added, the reaction proceeds in a direction of products.
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