Question

A 1.0L aqueous solution contains 0.25M PO43-. Solid indium nitrate In(NO3)3, is slowly added to the...

A 1.0L aqueous solution contains 0.25M PO43-. Solid indium nitrate In(NO3)3, is slowly added to the solution. The Ksp for InPO4=2.3x10-22 and Ksp for In(OH)3=1.3x10-37.

Assuming that the volume remains constant, calculate the following:

The [In3+] when InPO4 first starts to precipitate.

The [In3+] when In(OH)3 first starts to precipitate.

The [PO43-] when In(OH)3 first starts to precipitate.

I understand the neccessity to make ICE tables and calculate the concentrations, however my study group cant seem to figure out why solving the quadratics lead to extraneous solutions, and initial concentrations in steps following part 1 are also a tad confusing.

showing all steps would be highly appreciated.

Homework Answers

Answer #1

The Ksp for InPO4=2.3x10-22

Ksp for In(OH)3=1.3x10-37

here Ksp In(OH)3 < Ksp for InPO4

so In(OH)3 first precipitate

1)

InPO4   ----------------> In+3   +   PO43-

Ksp = [In+3][PO43-]

2.3x10-22 = [In+3 ] x 0.25

[In+3] = 9.2 x 10^-22 M

2)

In(OH)3   ---------------> In+3   + 3 OH-

Ksp = [In+3][OH-]^3

1.3x10-37 = 27 S^4

S = 2.63 x 10^-10

[In+3] = 2.63 x 10^-10 M

3)

InPO4   ----------------> In+3   +   PO43-

Ksp = [In+3][PO43-]

2.3x10-22 = 2.63 x 10^-10 x [PO43-]

[PO43-] = 8.73 x 10^-13 M

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