Question

13.00 grams of Fe(NO3)3 are dissolved in enough water to prepare 400.0ml of solution. How many...

13.00 grams of Fe(NO3)3 are dissolved in enough water to prepare 400.0ml of solution. How many ml of this solution would be be required to supply 0.134 moles of nitrate ions?

Homework Answers

Answer #1

first find the Molarity of the given solution

Molar mass of Fe(NO3)3,
MM = 1*MM(Fe) + 3*MM(N) + 9*MM(O)
= 1*55.85 + 3*14.01 + 9*16.0
= 241.88 g/mol
mass(Fe(NO3)3)= 13.00 g
number of mol of Fe(NO3)3,
n = mass of Fe(NO3)3/molar mass of Fe(NO3)3
=(13.0 g)/(241.88 g/mol)
= 5.375*10^-2 mol
volume , V = 400.0 mL
= 0.4 L
Molarity,
M = number of mol / volume in L
= 5.375*10^-2/0.4
= 0.1344 M

This is molarity of initial solution

Now we need 0.134 moles
use:
number of moles = Molarity * volume
0.134 moles = 0.01344 M * volume
volume = 9.97 L
Answer: 9.97 L

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Felicia dissolved 4.00 g of Co(NO3)2 in enough water to make 100 mL of stock solution....
Felicia dissolved 4.00 g of Co(NO3)2 in enough water to make 100 mL of stock solution. She took 4.00 mL of the stock solution and then diluted it with water to give 275 mL of a final solution. How many grams of NO3- ion are there in the final solution?
A. You wish to prepare 198 grams of 10.3 % Na3PO4. How many grams will need...
A. You wish to prepare 198 grams of 10.3 % Na3PO4. How many grams will need of sodium phosphate and how many mL of water? Assume that the density of water is 1.00 g / ml. B. If 20.5 grams of an aqueous solution of cobalt(II) sulfate, CoSO4, contains 2.84 grams of cobalt(II) sulfate, what is the percentage by mass of cobalt(II) sulfate in the solution? C. An aqueous solution of lead nitrate, Pb(NO3)2, contains 8.74 grams of lead nitrate...
A chemist dissolved 65.353 grams of CuSO4 * 5H2O into enough water to make 150.0 mL...
A chemist dissolved 65.353 grams of CuSO4 * 5H2O into enough water to make 150.0 mL of aqueous CuSO4 solution.    Please do D, I already know the answer to C (c)        He then reacted the above CuSO4  solution with some 0.225 M KI solution.  The reaction occurs as follows:            2 CuSO4 (aq) + 4 KI (aq) à 2 CuI (s) + I2 (aq) + 2 K2SO4 (aq) How many mL of the KI solution will be needed to completely precipitate out all the copper...
How many grams of Fe(CH3COO)3 are there in 202 grams of an aqueous solution that is...
How many grams of Fe(CH3COO)3 are there in 202 grams of an aqueous solution that is 11.6% by weight Fe(CH3COO)3? __ g Fe(CH3COO)3
40.0 mL of 2.0 M Fe(NO3)3 is mixed with 2 mL of 5 M Fe(NO3) and...
40.0 mL of 2.0 M Fe(NO3)3 is mixed with 2 mL of 5 M Fe(NO3) and 48 mL of water. What is the final molar concentration of Fe(NO3)? Answer is 1M but how do we get this solution? Please help.
for the equation 6 HNO+2Fe->3H2+2Fe(NO3)3, 21.4 grams of HNO3 is reacted with 20.3 grams Fe. How...
for the equation 6 HNO+2Fe->3H2+2Fe(NO3)3, 21.4 grams of HNO3 is reacted with 20.3 grams Fe. How many grams of Fe(NO3)3 will form?
3. Consider the following redox reaction, 3 Fe(NO3)2 (aq) + 2 Al (s) → 3 Fe...
3. Consider the following redox reaction, 3 Fe(NO3)2 (aq) + 2 Al (s) → 3 Fe (s) + 2 Al(NO3)3 (aq) a) Identify the species getting oxidized and the species getting reduced. b) If 6.3 moles of Fe(NO3)2 reacts with 5.4 moles of Al, which reactant is the limiting reactant? and c) How many grams of Al(NO3)3 will be produced?
When 50.0 mL of a 1.00 M solution of Fe(NO3)3 are mixed with 50.0mL of a...
When 50.0 mL of a 1.00 M solution of Fe(NO3)3 are mixed with 50.0mL of a 1.00 M solution of NaOH, a precipitate forms. What Ions remain after the reaction is complete? Fe(NO3)3 (aq) + 3 NaOH (aq) -> Fe(OH)3 (s) + 3 NaNO3 (aq) A. Fe3+, OH-, Na+, and NO3- B. Fe3+ and OH- C. Na+ and NO3- D. Fe3+, Na+, and OH-
Twenty-five gram of table salt (NaCl) is dissolved in enough water to make a solution. How...
Twenty-five gram of table salt (NaCl) is dissolved in enough water to make a solution. How many moles of NaCl are dissolved in water? 21.4 mole 4.27 × 10-1 mole 42.7 mole 2.14 × 10-1 mole
1.) A student found that the sulfate ion concentration in a solution of Al2(SO4)3 was 0.34...
1.) A student found that the sulfate ion concentration in a solution of Al2(SO4)3 was 0.34 M. What was the concentration of Al2(SO4)3 in the solution? C(Al2(SO4)3)= 2.) To study the effect of dissolved salt on the rusting of an iron sample, a student prepared a solution of NaCl by dissolving 4.250 g of NaCl in enough water to make 204.2 mL of solution. What is the molarity of this solution? C(NaCl) = 3.) A student found that the sulfate...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT