Question

The kinetic engergy of a 7.3 Kg steel ball traveling at 18.0 m/s is ______ J....

The kinetic engergy of a 7.3 Kg steel ball traveling at 18.0 m/s is ______ J.

Answer is 1.2x10^3. But I do not understand how to get it.

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Answer #1

Kinetic energy = 1/2 mV^2

                      = 1/2*7.3 *(18.0)^2

                      = 1182.6 J

                      = 1.1826 X10^3 J

                      = 1.2 *10^3 J

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