Question

What is the molarity of a base where 9.3 ml are used to neutralize .002 moles of an acid?

Answer 1

you did not mention is it mono basic acid or dibasic acid so i ma writing general equarion

Acid + Base ------> salt + water

from this equation one mole acid required one moles of base to complete nuetralization

he has given 0.002 moles of acid so obviously base is also 0.002 moles then only complete nuetralisation

now we know the moles of base and volume of base from this we can calculate the molarity

volume of Base = 9.3 mL convert in to liters = 9.3 / 1000 = 0.0093 L

now molarity = no of moles / volume liters

molarity of Base = 0.002 / 0.0093 = 0.215 M