Question

Determine the concentration of SO3 in the following reaction when it reaches equilibrium if the initial...

Determine the concentration of SO3 in the following reaction when it reaches equilibrium if the initial concentrations are 0.39 M So2, 0.14 M NO2, 0.11 M SO3 and 0.14 M NO.

SO2+NO2<=>SO3+NO       Kc=0.33

Please show all steps. Thank you!!

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Homework Answers

Answer #1

let x be the change at equilibrium

Kc = [SO3][NO]/[SO2][NO2]

0.33 = (0.11 + x)(0.14 + x)/(0.39 - x)(0.14 - x)

0.33 = 0.0154 + 0.25x + x^2/0.0546 - 0.53x + x^2

0.018 - 0.175x + 0.33x^2 = 0.0154 + 0.25x + x^2

0.67x^2 + 0.425x - 0.0026 = 0

Solving the quadratic equation,

x = [-b +/- sq.rt(b^2 - 4ac)]/2a

   = [-0.425 +/- ((0.425)^2 - (4 x 0.425 x -0.0026)]/2 x 0.67

   = [-0.425 + 0.433]/1.34

   = 0.006

x = 0.006 M

The equilibrium concentration of,

[SO3] = 0.11 + 0.006 = 0.116 M

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