Question

Calculate the percent yield of phenacetin obtained from the Williamson ether synthesis.

p-Acetamidophenol :1.510 g molar mass: 151.17g/mol

Bromoethane: 1.6 g molar mass: 108.97 g/mol

Final product: Phenacetin 0.904 g

Would appreciate an explanation and will like !

Answer 1

Ratio is:

p-Acetamidophenol + Bromoethane --> Phenacetin

CH3CONHC6H4OH + C2H5Br -->C10H13NO2

let it be A + B = C

ratio is 1:1

so

mol of A = 1.51/151.17 = 0.009988754

mol of B = 1.6/108.97 = 0.014682

mol of C = 0.904 /179.216 = 0.0050441

since ratio is 1:1 with respect to A and B

0.009988754 of A will form 0.009988754 of B

0.009988754 mol of C is expected

that is

mass of C = 0.009988754*179.216 = 1.7901

%yield = real/theoretical * 100 = 0.904/1.7901 * 100= 50.4999