Question

Calculate the pH and pOH in each of the following aqueous solutions. In each case, indicate whether the solution is acidic or basic. a) [OH-] = 1.33 x 10-8 M b) [OH-] = 1.06 x 10-9 M

Answer 1

(a) [OH^-] = 1.33 x 10^-8 M

pOH = - log[OH^-]

        = - log(1.33 x 10^-8)

        = 7.88

pH = 14 - pOH

     = 14 - 7.88

     = 6.12

Since the value of pH is less than 7 so the solution is acidic in nature.

(b) [OH^-] = 1.06 x 10^-9 M

pOH = - log[OH^-]

        = - log(1.06 x 10^-9)

        = 8.97

pH = 14 - pOH

     = 14 - 8.97

     = 5.03

Since the value of pH is less than 7 so the solution is acidic in nature.