Question

1.What is the chemical equation for titration of 3m of naOH into 1M HF including physical states?2.

2.What is the chemical equation for titration of 3M of NaOH into 1M of HCl including physical states?

2a. Does the titration of a Strong Acid with a Strong Base form a buffer? Explain. (Consider the products of the reaction in your explanation.)

2c. 4.   What is the equivalence point of any titration of Strong Acid with Strong Base?

Answer 1

1. Chemical equation for th titration of NaOH with HF will be,

1NaOH(aq) + 1HF(aq) ---> 1NaF(aq) + 1H2O(l)

So at the end 2 M of NaOH will remain unreacted.

2. Reaction of NaOH with HCl

1NaOH(aq) + 1HCl(aq) ----> 1NaCl(aq) + 1H2O(l)

Here again 1 mole of NaOH reacts with 1 mole of HCl. at the end 2 M of NaOH remains unreacted

2a. The titration of strong acid and strong base does not form a buffer. The pH remains to be neutral pH 7.

NaOH + HCl ----> NaCl + H2O

Na+ + OH- + H+ + Cl- ----> Na+ + Cl- + H2O(l)

H+ + OH- ---> H2O(l)

At equvalence point equal amounts of H+ and OH- are present in solution by complete dissociation of NaOH and HCl and thus pH will always be 7.

2c. Equivalence point of strong acid-strong base titration is always neutral that is pH 7 since equal number of H+ an OH- ions are present in solution.