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How many grams of sodium fluoride (NaF) would need to be added to 1.00 L of...

How many grams of sodium fluoride (NaF) would need to be added to 1.00 L of 0.19 M HF to yield a solution with pH = 4.93? (pKa of HF = 3.17)

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Answer #1

pH = pKa + log(salt/acid)

4.93 = 3.17 + log(salt/0.19)

log(salt/0.19) = 4.93-3.17

log(salt/0.19) = 1.76

log(salt)-log(0.19) = 1.76

log(salt)+0.72 = 1.76

log(salt) = 1.76-0.72

             = 1.04

[salt] = 10^1.04

        = 10.96 moles

mass of NaF = 10.96*42

                    = 460.32 grams

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