Question

Write the redox reaction between Sn2+ and MnO4- in acidic conditions. what is reduced/oxidized?

Write the redox reaction between Sn2+ and MnO4- in acidic conditions. what is reduced/oxidized?

Homework Answers

Answer #1

oxidation half reaction

Sn2+ (aq) ----> Sn4+ (aq) + 2e- -----1

reduction half reaction

MnO4- (aq) + 8H+ (aq) + 5e- -----> Mn2+ (aq) + 4H2O (l) ----2

in order to balace the electrons

multiply the equation1 with 5 and

equation 2 with 2

5Sn2+ (aq) ----> 5Sn4+ (aq) + 10e-

2MnO4- (aq) + 16H+ (aq) + 10e- -----> 2Mn2+ (aq) + 8H2O (l) add both equations

=======================================================

2MnO4- (aq) + 5Sn2+ (aq) + 16H+ (aq) -------.. 2Mn2+ (aq) + 5Sn4+ (aq) +8H2O (l) this is the balanced redox reaction

MnO4- get reduced

Sn2+ get oxidised

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