Calculate the energy, frequency, and wavelength required to remove the electron from the H atom, if the electron is in the n=2 energy level. Is the transition visible?
for Hydrogen,
En = -13.6/n^2 ev
So, energy for n=2 is,
E = -13.6/2^2 = -3.4 eV
1)
Energy required = 3.4 eV
E = 3.4 eV
= 3.4*1.602*10^-19 J
= 5.45*10^-19 J
Answer: 5.45*10^-19 J
2)
use:
E = h*f
5.45*10^-19J =(6.626*10^-34 J.s)*f
f = 8.225*10^14 Hz
Answer: 8.225*10^14 Hz
3)
use:
E = h*c/lambda
5.45*10^-19J =(6.626*10^-34 J.s)*(3.0*10^8 m/s)/lambda
lambda = 3.647*10^-7 m
Answer: wavelength = 3.647*10^-7 m
4)
wavelength = 3.647*10^-7 m
wavelength = 365 nm
wavelength of visible light is 400 nm to 700 nm
This is not in this range
Answer: no
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