Nitrogen trifluoride decomposes to form nitrogen and fluorine gases according to the following equation:
2NF3(g) N2(g) + 3F2(g)
When 3.15 mol of NF3 is placed in a 3.00-L container and allowed to come to equilibrium at 900 K, the mixture is found to contain 0.0563 mol of N2. What is the value of Kp at this temperature? (R = 0.0821 L⋅atm⋅mol-1⋅K-1). (Hint: Solve for Kc first, then calculate Kp)
a. 1.07 x 10–5
b. 1.91 x 10–3
c. 1.8 x 10–2
d. 1.11 x 10–5
e. 4.43 x 10–7
Please show work!
Answer is C 1.8 x 10–2
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