Question

Using the value of Ksp=6×10−51 for Ag2S, Ka1=9.5×10−8 and Ka2=1×10−19 for H2S, and Kf=1.1×105 for AgCl−2,...

Using the value of Ksp=6×10−51 for Ag2S, Ka1=9.5×10−8 and Ka2=1×10−19 for H2S, and Kf=1.1×105 for AgCl−2, calculate the equilibrium constant for the following reaction: Ag2S(s)+4Cl−(aq)+2H+(aq)⇌2AgCl−2(aq)+H2S(aq)

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the value of the equilibrium constant for the reaction below. Ksp for Ag2S is 6.0...
Calculate the value of the equilibrium constant for the reaction below. Ksp for Ag2S is 6.0 × 10−51...... Kf for Ag(NH3)2+ is 1.7 × 107. Ag2S(s) + 4 NH3(aq) ↔ 2 Ag(NH3)2+(aq) + S2−(aq)
Part A: Given the two reactions H2S⇌HS−+H+,   K1 = 9.51×10−8, and HS−⇌S2−+H+,   K2 = 1.33×10−19, what is the...
Part A: Given the two reactions H2S⇌HS−+H+,   K1 = 9.51×10−8, and HS−⇌S2−+H+,   K2 = 1.33×10−19, what is the equilibrium constant Kfinal for the following reaction? S2−+2H+⇌H2S Part B: Given the two reactions PbCl2⇌Pb2++2Cl−,   K3 = 1.83×10−10, and AgCl⇌Ag++Cl−,   K4 = 1.20×10−4, what is the equilibrium constant Kfinal for the following reaction? PbCl2+2Ag+⇌2AgCl+Pb2+
Part A Given the two reactions H2S⇌HS−+H+,   K1 = 9.20×10−8, and HS−⇌S2−+H+,   K2 = 1.18×10−19, what is the...
Part A Given the two reactions H2S⇌HS−+H+,   K1 = 9.20×10−8, and HS−⇌S2−+H+,   K2 = 1.18×10−19, what is the equilibrium constant Kfinal for the following reaction? S2−+2H+⇌H2S Enter your answer numerically. Kfinal = SubmitHintsMy AnswersGive UpReview Part Part B Given the two reactions PbCl2⇌Pb2++2Cl−,   K3 = 1.75×10−10, and AgCl⇌Ag++Cl−,   K4 = 1.28×10−4, what is the equilibrium constant Kfinal for the following reaction? PbCl2+2Ag+⇌2AgCl+Pb2+ Express your answer numerically.
A) Given the two reactions 1) H2S<--> HS- + H+, K1= 9.21x10^-8 and 2) HS- <-->...
A) Given the two reactions 1) H2S<--> HS- + H+, K1= 9.21x10^-8 and 2) HS- <--> S2- + H+, K2=1.59x10^-19, what is the equillibrium constant Kfinal for the following reaction? S2- + 2H+ <--> H2S B) Given the two reactions 3) PbCl2 <--> Pb2+ + 2Cl-, K3= 1.87x10^-10, and 4) AgCl <--> Ag+ + Cl-, K4= 1.11x10^4, what is the equillibrium constant Kfinal for the following reaction? PbCl2 + 2Ag+ <--> 2AgCl + Pb2+
H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.36×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.06×10−19, what is the equilibrium constant Kfinal for...
H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.36×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.06×10−19, what is the equilibrium constant Kfinal for the following reaction? S2−(aq)+2H+(aq)⇌H2S(aq)
(A) Using the Ksp for Cu(OH)2 (1.6 x 10^-19) and the overall formation constant for Cu(NH3)4...
(A) Using the Ksp for Cu(OH)2 (1.6 x 10^-19) and the overall formation constant for Cu(NH3)4 (1.0 x 10^13), calculate a value for the equilibrium constant for the reaction: Cu(OH)2(s) + 4NH3(aq) <===> Cu(NH3)4(aq) + 2OH-(aq) (B) Use the value of the equilibrium constant you calculated in Part A to calculate the (approximate) solubility (in mols/liter, M) of Cu(OH)2 in 5.0 M NH3. In 5.0 M NH3 the concentration of OH- is 9.5 x 10^-3 M. (Although not strictly correct...
1. For a certain reaction, Kc = 4.70×10−2 and kf= 95.6 M−2⋅s−1 . Calculate the value...
1. For a certain reaction, Kc = 4.70×10−2 and kf= 95.6 M−2⋅s−1 . Calculate the value of the reverse rate constant, kr, given that the reverse reaction is of the same molecularity as the forward reaction. Express your answer with the appropriate units. Include explicit multiplication within units, for example, to enter M−2⋅s−1 include ⋅ (multiplication dot) between each measurement 2. For a different reaction, Kc = 1.51×105, kf=8.12×103s−1 , and kr= 5.39×10−2 s−1 . Adding a catalyst increases the...
For the reaction A+B+C→D+EA+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants....
For the reaction A+B+C→D+EA+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The following data were collected: Trial [A][A] (MM) [B][B] (MM) [C][C] (MM) Initial rate (M/sM/s) 1 0.10 0.10 0.10 3.0×10−5 2 0.10 0.10 0.30 9.0×10−5 3 0.20 0.10 0.10 1.2×10−4 4 0.20 0.20 0.10 1.2×10−4 Question 1: Given the data calculated in Parts A, B, C, and D, determine the initial rate for a reaction that starts with 0.65 MM of reagent AA and...
1.         Write equilibrium (mass action) expressions for each of the following reactions: (a) H2(g) + I2(g)          2 HI...
1.         Write equilibrium (mass action) expressions for each of the following reactions: (a) H2(g) + I2(g)          2 HI (b)2 NO(g) + O2(g)           2 NO2(g) (c)N2(g) + 3 H2(g)           2 NH3(g) (d) CO(g) + NO2(g)           CO2(g) + NO(g) (e) 2 CO(g) + O2(g)             2 CO2(g) 2.    Write equilibrium expressions for each of the following equilibria: (a) 2 C(s) + O2(g)                  CO(g) (b) Zn2+(aq) + H2S(g)               ZnS(s) + 2 H+(aq) (c) HCl(g) + H2O()                  H3O+(aq) + Cl–(aq) (d)H2(g) +  O2(g)                   H2O(g) 3.         Which of the following is more likely to precipitate the hydroxide ion? (a)...
1. What is the pH of a 0.000682 M solution of NaOH? 2. a)What is the...
1. What is the pH of a 0.000682 M solution of NaOH? 2. a)What is the kb for F- given that the ka for HF is 6.8*10-4 b)What is the pH of a 0.292 M solution of NaF? 3. What is the pH of a 0.03 M solution of CaO? HINT: CaO is ionic and dissociates into ions. What is the oxygen ion that results? What kind of an acid or base is it? You need to write out the...