Question

Calculate the molarity of the following solutions.

0.650 mole glucose in 0.100 L of a glucose solution

83.0 g of HCl in 2.50 L of a HCl solution

33.0 g of NaOH in 400. mL of a NaOH solution

Answer 1

0.650 mole glucose in 0.100 L of a glucose solution

we can write it, 6.5 moles glucose in 1L of solution.

Thus, it is 6.5M glucose solution

83.0 g of HCl in 2.50 L of a HCl solution

83.0 g of HCl is 2.27moles

Thus, 2.27 moles present in 2.5L solution

=> 0.91 moles present in 1L of solution

Thus its sterngth is 0.91 M.

33.0 g of NaOH in 400. mL of a NaOH solution

33.0 g of NaOH is 0.825 moles

So, 0.825 moles present in 400 mL of solution

=> 0.00206 moles present in 1 mL of solution

=> 2.06 moles present in 1000 mL of solution

Thus, its strength is 2.06 M.