Question

500ml of 0.120 M NaOH is added to 565ml of 0.200 M weak acid (Ka=4.80x10^-5). what...

500ml of 0.120 M NaOH is added to 565ml of 0.200 M weak acid (Ka=4.80x10^-5). what is the ph of the resulting buffer?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
500.0 mL of 0.120 M NaOH is added to 605 mL of 0.250 M weak acid...
500.0 mL of 0.120 M NaOH is added to 605 mL of 0.250 M weak acid (Ka = 4.44 × 10-5). What is the pH of the resulting buffer?
500 mL OF 0.120 M NaOH IS ADDED TO 605 mL OF .200 M WEAK ACID...
500 mL OF 0.120 M NaOH IS ADDED TO 605 mL OF .200 M WEAK ACID (Ka= 4.39X10-5). WHAT IS THE PH OF THE RESULTING BUFFER. HA(aq) + OH-(aq) -------> H2O (L) + A-
500.0 mL of 0.140 M NaOH is added to 615 mL of 0.200 M weak acid...
500.0 mL of 0.140 M NaOH is added to 615 mL of 0.200 M weak acid (Ka = 4.06 × 10-5). What is the pH of the resulting buffer?
500.0 mL of 0.110 M NaOH is added to 585 mL of 0.200 M weak acid...
500.0 mL of 0.110 M NaOH is added to 585 mL of 0.200 M weak acid (Ka = 7.30 × 10-5). What is the pH of the resulting buffer?
500.0 mL of 0.130 M NaOH is added to 575 mL of 0.200 M weak acid...
500.0 mL of 0.130 M NaOH is added to 575 mL of 0.200 M weak acid (Ka = 7.35 × 10-5). What is the pH of the resulting buffer?
500.0 mL of 0.170 M NaOH is added to 575 mL of 0.250 M weak acid...
500.0 mL of 0.170 M NaOH is added to 575 mL of 0.250 M weak acid (Ka = 1.50 × 10-5). What is the pH of the resulting buffer?
500.0 mL of 0.100 M NaOH is added to 575 mL of 0.250 M weak acid...
500.0 mL of 0.100 M NaOH is added to 575 mL of 0.250 M weak acid (Ka = 3.61 × 10-5). What is the pH of the resulting buffer?
500.0 mL of 0.160 M NaOH is added to 575 mL of 0.250 M weak acid...
500.0 mL of 0.160 M NaOH is added to 575 mL of 0.250 M weak acid (Ka = 2.43 × 10-5). What is the pH of the resulting buffer?
A volume of 500.0 mL of 0.100 M NaOH is added to 535 mL of 0.200...
A volume of 500.0 mL of 0.100 M NaOH is added to 535 mL of 0.200 M weak acid (?a=4.69×10^−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
Strong base is dissolved in 545 mL of 0.200 M weak acid (Ka = 4.02 ×...
Strong base is dissolved in 545 mL of 0.200 M weak acid (Ka = 4.02 × 10-5) to make a buffer with a pH of 4.11. Assume that the volume remains constant when the base is added. a) Calculate the pKa value of the acid and determine the number of moles of acid initially present. b) When the reaction is complete, what is the concentration ratio of conjugate base to acid? c) How many moles of strong base were initially...