Cyanic acid, HCNO, is a weak acid with the following equilibrium: HCNO(aq) + H2O(l) ⇌ CNO-(aq) + H3O+(aq) In a 0.200 M aqueous solution of HCNO, the concentration of H3O+ is 6.50 x 10-3M. The equilibrium constant (Kc) for this reaction is?
HCNO(aq) + H2O(l) <----------------------> CNO-(aq) + H3O+(aq)
0.200 6.50 x 10-3 6.50 x 10-3
[CNO-] = [H3O+]
Kc = [CNO-] [H3O+] / [HCNO]
Kc = ( 6.50 x 10^-3)^2 / 0.200
Kc = 2.11 x 10^-4
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