Question

15 ^OC, where the pure vapor pressures are 12.5 mmHg for water and 32.1 mmHg for ethanol. According to Raoult’s Law, the pressure of a component in a solution is equal to its pure vapor pressure times its mole fraction, that is P_A = () (X_A). Use Raoult’s law to determine the vapor pressure of each component in the solution. Then, add them to find the total vapor pressure. Show all equations and conversion factors

Answer 1

P^Owater = 12.5 mmHg

P^Oethanol = 32.1 mmHg

Pwater = Po x mole fraction

               = 12.5 x mole fraction of water

Pethanol = Po x mole fraction of ethanol

               = 32.1x mole fraction of ethanol

total pressure = Pwater + Pethanol

Total pressure = 12.5 x mole fraction of water + 32.1 x mole fraction of water

note: you did not give molefractions of water and ethanol . i need at least masses or percent i can complete this problem