Question

Consider this reaction: 4NH3 + 5O2 --> 4NO + 6H2O If you start with 5.5 moles of NH3 and 8 moles of O2, then: how many moles of NO can be formed? how many moles of H2O can be formed?

Answer 1

4NH3 + 5O2 -----> 4NO + 6H2O

Part A

a) 4 moles of NH3 gives-------> 4 moles of NO

   5.5 moles of NH3 gives------->4*5.5/4 = 5.5 moles of NO

b) 5 moles of O2 gives-------> 4 moles of NO

8 moles of O2 gives ----> 4*8/5 = 6.4 moles of NO

Moles of NO formed = 5.5 moles.

Part B

a) 4 moles of NH3 gives-------> 6 moles of H2O

   5.5 moles of NH3 gives-------> 6*5.5/4 = 8.25 moles of H2O

b) 5 moles of O2 gives-------> 6 moles of H2O

8 moles of O2 gives ----> 8*6/5 = 9.6 moles of H2O

moles of H2O formed = 8.25 moles.