Question

Addition of a strong acid to a solution of acetic acid at equilibrium (HOAc + H2O...

Addition of a strong acid to a solution of acetic acid at equilibrium (HOAc + H2O <--> H3O+ + OAc-) would cause the:

a. acetate ion concentration to decrease.
b. acetate ion concentration to increase.
​c. pH to increase
d. hydroxide ion concentration to increase.
e. None of the above is correct.

I know the correct answer is a, but I cannot figure out why. If anyone could explain why this is the answer, I'd greatly appreciate it!

Homework Answers

Answer #1

a strong acid is an acid that ionizes completely by losing one proton.

but weak acids are an acids that dissociates incompletely, releasing only some of its hydrogen atoms into the solution. Thus, it is less capable than a strong acid at donating protons.

Acetic acid ionize in water solution to only a moderate extent. If we decrease the H+ ion concentraion by reacting with base some more acetic acid will ionize to maintain the pKa. in the same way If we increase the H+ ion concentraion by adding some strong acid some more H+ ions will ion form acetic acid to maintain the same pKa. it mostly depends on H+ concentration.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Sodium acetate (NaOAc) is the sodium salt of the conjugate base of acetic acid (HOAc). Although...
Sodium acetate (NaOAc) is the sodium salt of the conjugate base of acetic acid (HOAc). Although NaOAc is a strong electrolyte, the acetate ion itself (OAc−) is a weak base. Assume pKa = 4.76 for HOAc. 1) Calculate the pH of a 50.0 mM HOAc solution. Using a 5% criterion, explicitly check any approximations you make to ensure they are valid. 2) Calculate the pH of a 50.0 mM NaOAc solution. Again, check your assumptions.
Write the chemical equation for the ionization of acetic acid. CH3CO2H + H2O <---> H3O+ +...
Write the chemical equation for the ionization of acetic acid. CH3CO2H + H2O <---> H3O+ + CH3CO2- From the pH, calculate the concentration of hydrogen ions. ( I KNOW TO USE THIS ph = -log[H+]) Next, find the concentration of theacetate ion. (I HAVE NO IDEA HOW TO DO THIS PART) How would the concentration of hydrogen ion be related to the acetate ion? (Hint: lookat the formula for acetic acid.) Considering that acetic acid is the source of hydrogen...
a) A solution was prepared by dissolving 0.02 moles of acetic acid (HOAc; pKa = 4.8)...
a) A solution was prepared by dissolving 0.02 moles of acetic acid (HOAc; pKa = 4.8) in water to give 1 liter of solution. What is the pH? b) To this solution was then added 0.008 moles of concentrated sodium hydroxide (NaOH). What is the new pH? (In this problem, you may ignore changes in volume due to the addition of NaOH). c) An additional 0.012 moles of NaOH is then added. What is the pH?
Hi! i need to calculate the Ka for acetic acid from an experiment using an ice...
Hi! i need to calculate the Ka for acetic acid from an experiment using an ice diagram but my Ka value keeps coming up negative. I'm using the pH of the acetic acid before titration with NaOH (pH = 2.96) to get [H3o+] and [OAc] to equal 10^(-2.96) which is 1.1x10-3. And the moles of acid in my original flask was 0.004 HOAc, so can someone show me the calculations if I am doing them wrong or help me figure...
One beaker contains 10.0 mL of acetic acid/sodium acetate buffer at maximum buffer capacity (equal concentrations...
One beaker contains 10.0 mL of acetic acid/sodium acetate buffer at maximum buffer capacity (equal concentrations of acetic acid and sodium acetate), and another contains 10.0 mL of pure water. Calculate the hydronium ion concentration and the pH after the addition of 0.25 mL of 0.10 M HCl to each one. What accounts for the difference in the hydronium ion concentrations? Explain this based on equilibrium concepts; in other words, saying that “one solution is a buffer” is not sufficient....
1.) You will work with 0.10 M acetic acid and 17 M acetic acid in this...
1.) You will work with 0.10 M acetic acid and 17 M acetic acid in this experiment. What is the relationship between concentration and ionization? Explain the reason for this relationship 2.) Explain hydrolysis, i.e, what types of molecules undergo hydrolysis (be specific) and show equations for reactions of acid, base, and salt hydrolysis not used as examples in the introduction to this experiment 3.) In Part C: Hydrolysis of Salts, you will calibrate the pH probe prior to testing...
When 1.0 mole of acetic acid is diluted with water to a volume of 1.0 L...
When 1.0 mole of acetic acid is diluted with water to a volume of 1.0 L at 25 C, 0.42% of the acetic acid ionizes to form acetate ion and hydronium ion. CH3CO2H(aq) + H2O(l) = CH3CO2–(aq) + H3O+(aq) What percentage of the acid ionizes when 0.75 mole of acetic acid is diluted with water to 1.0 L at 25 C? Can you show the answer step by step so I can figure out how to do the other examples...
1) What is the concentration of acetic acid in the 0.100M pH 5.000 buffered solution? Note...
1) What is the concentration of acetic acid in the 0.100M pH 5.000 buffered solution? Note 1: Based on the notation you use, you may write that the acetic acid concentration as either [HOAc] or Ca. Note 2: Don't forget that the formal buffer concentration is 0.1M. Note 3: Enter your answer below in three signficant figures. Don't worry about writing the units. 2) What mass of sodium acetate (NaOAc, 82.03 g/mol) would be needed to prepare 1L of the...
A.) A 1 liter solution contains 0.343 M acetic acid and 0.457 M sodium acetate. Addition...
A.) A 1 liter solution contains 0.343 M acetic acid and 0.457 M sodium acetate. Addition of 0.377 moles of calcium hydroxide will: (Assume that the volume does not change upon the addition of calcium hydroxide.) Raise the pH slightly Lower the pH slightly Raise the pH by several units Lower the pH by several units Not change the pH Exceed the buffer capacity B.) A 1 liter solution contains 0.340 M hydrocyanic acid and 0.453 M sodium cyanide. Addition...
1The hydroxide ion concentration of an aqueous solution of 0.563 M formic acid , HCOOH is...
1The hydroxide ion concentration of an aqueous solution of 0.563 M formic acid , HCOOH is [OH-] = (answer) M. 2 The hydronium ion concentration of an aqueous solution of 0.563 M acetic acid (Ka = 1.80×10-5) is [H3O+] = (Answer) M.