Question

A sample of 447.9 mg of hydroxylamine (NH2OH) is dissolved in 55.5 mL of DI H2O....

A sample of 447.9 mg of hydroxylamine (NH2OH) is dissolved in 55.5 mL of DI H2O. This sample is to be titrated with 0.315 M HClO4 . Fill in the following table for each different point (a, b, c, etc….) during the titration. (Make sure all work is attached for credit). Also graph the titration curve with pH on the y­axis and Vbase on the x­axis.

Point |Vbase (mL)| molbase added| mol acid remain| molbase remain| [OH ­ ]| [H3O + ]| pH|

a            0.00

b           7.50

c           13.75

d           38.90

e            Veq=

f            50

Homework Answers

Answer #1
Point

VBase(mL)

Mol base added Mol acid remain Mol base remanin [OH-] [H3O+] pH
a

0.00

0.0000

0.0111 0.0000 0.0000 0.0110 1.96
b 7.50 0.0018 0.0092 0.0000 0.0000 0.0092 2.04
c 13.75 0.0034 0.0077 0.0000 0.0000 0.0077 2.12
d 38.90 0.0095 0.0015 0.0000 0.0000 0.0015 2.81
e Veq=45.08 0.0110 0.0000 0.0000 0.0000 0.0000 4.60
f 50 0.0122 0.0000 0.0012 0.0012 0.0000 11.07

Note: assume a 35mL of HClO4 because you do not know the volume of acid

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