Question

A) HClO is a weak acid (Ka = 4.0 × 10–8) and so the salt NaClO acts as a weak base. What is the pH of a solution that is 0.087 M in NaClO at 25 °C? The hint is: Na is a spectator ion in this situation. Start by finding the Kb of ClO–.

B) A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density of bleach is the same as water, calculate the volume of household bleach that should be diluted with water to make 500.0 mL of a pH = 10.26 solution. The hint states Hypochlorite ion, OCl–, is sometimes written as ClO–. Its conjugate acid, hypochlorous acid, can be written either as HOCl or HClO. Use the Ka of hypochlorous acid to determine the Kb of hypochlorite. Ka =4.0×10–8

Any explanations would be greatly appreciated.

Answer 1