Question

Calculate Δ_mixS, Δ_mixH, and Δ_mixG for mixing two liquids, A and B in equal amounts at 300 K. Assume the mixture is ideal.

Δ_mixS in J/mol K

Δ_mixH in kj/mol K

Δ_mixG in kj/mol K

I know Δ_mixH is equal to 0 kj/mol K but I cannot figure out the other two.

Answer 1

For mixing of an ideal solution Δ_mixH in kj/mol K = 0

                                           Δ_mixS in J/mol K = 0

                                         Δ G = ΔH- TΔS

                                       Δ_mixG in kj/mol K = 0