Question

8.10 kj of heat energy is added to 15.0 g of ice at -25.0c describe the...

8.10 kj of heat energy is added to 15.0 g of ice at -25.0c describe the final state and temperatures
Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Total Heat added = 8.1 kJ = 8100 J

calcualte heat required to heat ice form -25°C to 0°C

Cp ice = 2.01 J/g

Q = m*Cice*(Tf-Ti)

Q = 15* 2.01*(0 +25) = 753.75 J

Q = 753.75 J...

Q left = 8100-753.75 = 7346.25 J

Calculate heat required to melt ice to water

Q = m*LH

where LH = latent heat of fussion

Q = 15 g*334 J/g = 5010 J

Qleft = 7346.25 -5010 = 2336.25 J

now...

Q = m*Cpwater * (Tf-Ti)

Ti = 0°C, m = 15 g and Q left = v

solve for Tf

Tf = Q/(m*Cp) + Ti

Tf = 2336.25/(15*4.184) + 0

Tf = 37.23 °C

final state is water at 37°C

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 25.0-g glass tumbler contains 200 mL of water at 24.0ºC. If two 15.0-g ice cubes,...
A 25.0-g glass tumbler contains 200 mL of water at 24.0ºC. If two 15.0-g ice cubes, each at a temperature of –3.00ºC, are dropped into the tumbler, what is the final temperature of the drink? Neglect any heat transfer between the tumbler and the room. (Specific heat of water and ice are 4.186 kJ/(kg K) and 2.05 kJ/(kg K), respectively. The latent heat of fusion of water is 333.5 kJ/kg. The specific heat of glass is 0.840 kJ/(kg K )....
If 133.2 kJ of heat are added to 5.80 × 102 g of water at 22.0°C,...
If 133.2 kJ of heat are added to 5.80 × 102 g of water at 22.0°C, what is the final temperature of the water? Specific heat of water at 1.00 atm and 20.0°C is 4.186 kJ/kg·K.
A.) How much heat is required to convert 15.0 g of ice at -13.0 ∘C to...
A.) How much heat is required to convert 15.0 g of ice at -13.0 ∘C to steam at 100.0∘C ? Express your answer using three significant figures. (Joules) B.)How much heat is required to convert 15.0 g of ice at -13.0 ∘C to steam at 100.0∘C? Express your answer using three significant figures. (kcal)
What amount of thermal energy (in kJ) is required to convert 220 g of ice at...
What amount of thermal energy (in kJ) is required to convert 220 g of ice at -18 °C completely to water vapour at 248 °C? The melting point of water is 0 °C and its normal boiling point is 100 °C. The heat of fusion of water is 6.02 kJ mol-1 The heat of vaporization of water at its normal boiling point is 40.7 kJ mol-1 The specific heat capacity of ice is 2.09 J g-1 °C-1 The specific heat...
What amount of thermal energy (in kJ) is required to convert 216 g of ice at...
What amount of thermal energy (in kJ) is required to convert 216 g of ice at -30 °C completely to water vapour at 198 °C? The melting point of water is 0 °C and its normal boiling point is 100 °C. The heat of fusion of water is 6.02 kJ mol-1 The heat of vaporization of water at its normal boiling point is 40.7 kJ mol-1 The specific heat capacity of ice is 2.09 J g-1 °C-1 The specific heat...
803 cal of heat is added to 5.00 g ice at –20.0 °C. What is the...
803 cal of heat is added to 5.00 g ice at –20.0 °C. What is the final temperature of the water? SPecific heat H2O(s)= 2.087 J/(g*C) Specific heat H2O(l)=4.184 J/(g*C) Heat of fusion= 333.6 J/g
When 15.0 g of ice at 0°C is melted in 100 g of water at 20.0°C,...
When 15.0 g of ice at 0°C is melted in 100 g of water at 20.0°C, the final temperature is 9.5°C. Find the heat of fusion of ice, based on this data.
How much heat (in kJ) is required to warm 12.0 g of ice, initially at -12.0...
How much heat (in kJ) is required to warm 12.0 g of ice, initially at -12.0 ∘C, to steam at 112.0 ∘C? The heat capacity of ice is 2.09 J/g⋅∘C and that of steam is 2.01 J/g⋅∘C. kJ
The heat of fusion of ice is 335 J/g. When 40.968 g of ice at 0øC...
The heat of fusion of ice is 335 J/g. When 40.968 g of ice at 0øC is added to 222.298 g of water at 67.978øC, what is the final temperature?
A quantity of ice at 0.0 °C was added to 33.6 g of water at 41.0...
A quantity of ice at 0.0 °C was added to 33.6 g of water at 41.0 °C to give water at 0.0 °C. How much ice was added? The heat of fusion of water is 6.01 kJ/mol, and the specific heat is 4.18 J/(g•°C). ______ grams
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT