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Will the calculated molarity of the NaOH solution be too high or too low if a...

Will the calculated molarity of the NaOH solution be too high or too low if a student "overshoots" the end point of the titration? Explain.

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Answer #1

If the student "overshoots" the molarity will be higher since:

Molarity of Acid = mol of acid / volume of acid initially

since the volume of acid initally is the same then the only thing that changes is mol of acid

mol of acid is related to mol of base

mol of base = MV

since M of base is known

and Volume is being analyzsed, then if we overshoot, that is, exceed the amount of volume needed, then we will have a higher count of base, if this happens, we rlate mol of acid higher!

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