Question

How much ice (in grams) would have to melt to lower the temperature of 350 mL of water from 26 ∘C to 4 ∘C? (Assume the density of water is 1.0 g/mL.) Express your answer using two significant figures.

Answer 1

mass of water= volume of water* density of water= 350 ml*1g/ml= 350 gm

specific heat of water= 4.184 J/gm.deg.c

heat to be removed from water in bringing the temperature from 26 deg.c to 4 deg.c= mass* specific heat of water* temperature difference= 350*4.184*(26-4) =32217 joules

during melting of ice, latent heat of fusion is added. heat of fusion of ice= 333.55 J/gm

mass of ice required to be melted= heat to be removed/ latent heat of fusion of ice= 32217/333.55 =96.6 gm