Question

In chemistry I'm having problems solving equilibrium problems because I don't know how to rearrange the equation:

how do you reaarange this:

given: kp = 0.997

0.997= [3.00]^2 [O2] / [0.520]^2 you need to find [O2]. I don't need you to actually solve this, just provide me with examples of how to set this up so I can solve for [O2]

or if you have:

k=[0.1-x]^2 [0.5-2x]^3 / [2.3-3x]^2

Answer 1

Tip 1:

many times you may simplify i.e.

15 = x*x / (2-x)(2-x)

15 = x^2 / (2-x)^2

sqrt(15) = sqrt( x^2 / (2-x)^2)

3.87 = x/(2-x)

then you solve easily

3.87(2-x) = x

3.87*2 = (3.87+1)x

x = 3.87*2/(4.87) = 1.589

For complex problems

suc as

1=[0.1-x]^2 [0.5-2x]^3 / [2.3-3x]^2

I personally split this into right side and left side, then take care of degree

so pass the division to the left

1 * [2.3-3x]^2 =[0.1-x]^2 [0.5-2x]^3

expan

(2.3^2 -3*2.3x + 9x^2) = (0.1^2 -0.2x+ x^2) (0.5^3 +3*0.5^2*(-2)x + 3*(0.5)(-2x)^2) + 8x^3)

then send all

Ax^3 + Bx^2 + Cx + D = 0

usually I use a calcualtor to solve for x