Briefly explain how the Mg to O ratio would have been affected if you had failed to convert all of the MG3N2 present to magnesium oxide.
The initial value
Mg3N2(s) --> MgO(s) + N2(g)
we need to addd O2(g) for oxidatio nto occur
balance
2Mg2N2 + O2 = MgO + N2
now, balance
2Mg3N2 + 3O2 → 6MgO + 2N2
ratio is we fail Mg3N2 vs MgO
if we fail to convert all
There will be present:
Mg3N2 --> MW = 100.9284 g/mol
MgO --> MW = 40.3044 g/mol
In the end, we will assume most of this is MgO
then Mg3N2 will be an impurity
This will increase the mass of our sample
which will lower our ratio
Since
Total Mg species = Mg3N2 and MgO
Mg higher in ratio in Mg3N2 tan MgO
therefore, the ratio is Mg >> O
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