Question

Given the following reactions:

Question (1)

Calculate for the change in enthalpy of the reaction of (3Fe2O3(s) + CO(g) yields CO2(g) + 2Fe3O4(s))

Fe2O3(s) + 3CO(g) yields 2Fe(s) + 3CO2(s)(Change in enthalpy= -28.0 kJ)

3Fe(s) + 4CO2(s) yields 4CO(g) + FE3O4(s) (Change in enthalpy= +12.5 kJ)

Answer #1

Fe2O3(s) + 3CO(g) yields 2Fe(s) + 3CO2(s) (Change in enthalpy= -28.0 kJ)

multiply above equation with 3

3Fe2O3(s) + 9CO(g) yields 6Fe(s) + 9CO2(s) (Change in enthalpy= -84.0 kJ) -------------- (1)

3Fe(s) + 4CO2(s) yields 4CO(g) + Fe3O4(s) (Change in enthalpy= +12.5 kJ)

multiply equation with 2

2Fe(s) + 8CO2(s) yields 8CO(g) + 2Fe3O4(s) (Change in enthalpy= +25 kJ) --------------------(2)

add equation 1 and 2

3Fe2O3(s) + 9CO(g) yields 6Fe(s) + 9CO2(s) (Change in enthalpy= -84.0 kJ) -------------- (1)

6Fe(s) + 8CO2(s) yields 8CO(g) + 2Fe3O4(s) (Change in enthalpy= +25 kJ) --------------------(2)

--------------------------------------------------------------------------------------------------------------------------------------------------

**3Fe2O3(s) + CO(g) yields CO2(g) + 2Fe3O4(s)) chanhe in
enthalpy = - 59 .0KJ**

Given the following data:
2Fe(s) + 3CO2(g) → Fe2O3(s) +
3CO(g)
ΔH° = 23.0 kJ
3FeO(s) + CO2(g) → Fe3O4(s) +
CO(g)
ΔH° = -18.0 kJ
3Fe2O3(s) + CO(g) →
2Fe3O4(s) + CO2(g)
ΔH° = -39.0 kJ
Calculate ΔH° for the reaction:
Fe(s) + CO2(g) → FeO(s) + CO(g)

Calculate the enthalpy of reaction for the following reaction:
Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) ΔHfo(Fe2O3(s)) = -824.2 kJ/mol
ΔHfo(CO(g)) = -110.5 ΔHfo(Fe(s)) = ? ΔHfo(CO2(g)) = -393.5
kJ/mol

Calculate ΔHrxn for the following reaction:
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)
Use the following reactions and given ΔH′s.
2Fe(s)+3/2O2(g)→Fe2O3(s), ΔH =
-824.2 kJ
CO(g)+1/2O2(g)→CO2(g), ΔH =
-282.7 kJ

Calculate the ΔH for the following
reaction:
Fe2O3
+ 3 CO → 2 Fe + 3
CO2
based on the reactions below.
3Fe2O3
+
CO→2Fe3O4
+ CO2
ΔH=−48.5kJ
Fe+CO2
→FeO+CO.
ΔH=−11.0kJ
Fe3O4
+CO→3FeO+CO2
ΔH=+22.0kJ

Use the information provided to determine
ΔrH° for the following reaction:
ΔfH° (kJ
mol-1) 3Fe2O3(s)
+ CO(g) → 2Fe3O4(s) +
CO2(g) ΔrH° =
?
Fe2O3(s) -824
Fe3O4(s) -1118
CO(g) -111
CO2(g) -394
Answers:
-577 kJ mol-1
+144 kJ mol-1
+277 kJ mol-1
-47 kJ mol-1
-111 kJ mol-1

Calculate ΔG° for the reduction of Fe2O3 by CO at 25°C: Fe2O3(s)
+ 3CO(g) → 2Fe(s) + 3CO2(g) (ΔG°f data: CO2(g), –394.4 kJ/mol;
Fe2O3(s), –741.0 kJ/mol; CO(g), –137.3kJ/mol) (Consider: Is the
value that you calculate for ΔG° here the same value that you
calculated for ΔG° using ΔH°f and S° data in the other
question?)
+60.6 kJ
-60.6 kJ
-30.3 kJ
+30.3 kJ
-15.1 kJ

At 1000 K, Kp = 19.9 for the reaction
Fe2O3(s)+3CO(g)⇌2Fe(s)+3CO2(g).
What are the equilibrium partial pressures of CO and CO2 if CO
is the only gas present initially, at a partial pressure of 0.940
atm ?

A chemist measures the enthalpy change ΔH during the following
reaction: 2Al (s) + Fe2O3 (s) → Al2O3 (s) + 2Fe (s) =ΔH−852.kJ
Use this information to calculate ΔH in kJ for the following
reactions:
3Al2O3s + 6Fes → 6Als +
3Fe2O3s
Al2O3s + 2Fes → 2Als +
Fe2O3s
4Als + 2Fe2O3s → 2Al2O3s +
4Fes

3)From the following data at 25C ∆Hreaction (kJ
mol-1)
Fe2O3(s) + 3C(graphite) → 2Fe(s) + 3CO(g) 492.6
FeO(s) + C(graphite) → Fe(s) + CO(g) 155.8
C(graphite) + O2(g) → CO2(g)
-393.51
CO(g) + 1⁄2 O2(g) → CO2(g) -282.98
Calculate the standard enthalpy of formation of FeO(s) and of
Fe2O3(s).

The reaction of iron(III) oxide with carbon monoxide is
important in making steel. At 1000 K, Kp=19.9 for the reaction
Fe2O3(s) + 3CO(g) <-----> 2Fe(s) + 3CO2(g). What are the
equilibrium partial pressures of CO and CO2 if CO is the only gas
present initially, at a partial pressure of 0.978 atm?

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