Ammonium nitrate decomposes explosively upon heating according to the following balanced equation: 2NH4NO3(s)→2N2(g)+O2(g)+4H2O(g)
a.) Calculate the total volume of gas (at 121 ∘C and 767 mmHg ) produced by the complete decomposition of 1.62 kg of ammonium nitrate.
Molar mass of NH4NO3,
MM = 2*MM(N) + 4*MM(H) + 3*MM(O)
= 2*14.01 + 4*1.008 + 3*16.0
= 80.052 g/mol
mass of NH4NO3 = 1.62 Kg = 1.62*10^3 g
mol of NH4NO3 = (mass)/(molar mass)
= 1.62*10^3/80.05
= 20.24 mol
According to balanced equation
mol of gas formed = (7/2)* moles of NH4NO3
= (7/2)*20.24
= 70.83 mol
Given:
P = 767.0 mm Hg
= (767.0/760) atm
= 1.0092 atm
n = 70.83 mol
T = 121.0 oC
= (121.0+273) K
= 394 K
use:
P * V = n*R*T
1.0092 atm * V = 70.83 mol* 0.08206 atm.L/mol.K * 394 K
V = 2269.15 L
Answer: 2.23*10^3 L
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