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20.40g Iron(III) oxalate is dissolved in enough water to give 250.0 ml of solution. 25.00 ml...

20.40g Iron(III) oxalate is dissolved in enough water to give 250.0 ml of solution. 25.00 ml of this solution is pipetted into a 100.0ml volumetric flask and diluted to the mark.

A. Calculate the molarity of Iron(III) oxalate in the original solution.

B. Calculate the molarity of the oxalate ion in the diluted solution.

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Homework Answers

Answer #1

molarmass of Fe2(C2O4)3 = 375.747 g/mol

VOLUME OF SOLUTION = 250 ml = 0.25 L

Molarity = w/mwt*1/V in L


w = 40 grams , Mwt = 375.747 g/mol

V = 0.25 L

Molarity = (40/375.747)*(1/0.25)

           = 0.426 M

A. the molarity of Iron(III) oxalate in the original solution. = 0.426 M

B . molarity of the oxalate ion in the diluted solution.


M1V1 = M2V2

M1 = 0.426 M , V1 = 25 ml

M2 = ?           v2 = 100 ml

M2 = M1V1/V2 = 0.426*25/100 = 0.1065 M

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