Question

Suppose hydrochloric acid reacts with potassium sulfite yielding water, sulfur dioxide, and potassium chloride. Suppose 4 moles of hydrochloric acid react with excess potassium carbonate. How many grams of sulfur dioxide are produced? Enter only a numerical value, do not enter units.

Answer 1

I suppose there is a mistake in the third line. It should be potassium sulfite but written as potassium carbonate.

Based on the description given, the reaction is as follows..

K₂SO₃ + 2HCl -----> SO₂ + 2KCl + H₂O

From the equation, it is clear that every two moles of HCl produce one mole of SO2.

Then every four moles of HCl will produce two moles of SO2.

Since moles = weight / molar mss

weight = moles x molar mss

molar mass of SO2 = 64.066 g/mol

weight of SO2 = 2 x 64.066

= 128.132