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A certain reaction has an activation energy of 31.40 kJ/mol. At what Kelvin temperature will the...

A certain reaction has an activation energy of 31.40 kJ/mol. At what Kelvin temperature will the reaction proceed 6.50 times faster than it did at 293 K?

Use the Arrhenius equation

ln (k2/k1) = Ea/R [(1/T1)-(1/T2)]

Where R=8.3145 J/(molxK)

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