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Calculate the pH of the following solutions: 2.4 M KOH, 0.060 M NaOH

Calculate the pH of the following solutions: 2.4 M KOH, 0.060 M NaOH

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Answer #1

2.4 M KOH

  • Dissociation Reaction

As KOH is a strong base it is completely dissociates in water. Therefore  the concentration of the ions equals the concentration of the base

KOH (2.4M) ------> K+(2.4M) + OH-(2.4M)

  • Calculate pOH

pOH=-Log[OH-]= -Log(2.4)= -0.38

  • Calculate pH

pH + pOH = 14

pH=14- pOH= 14-(-0.38) = 14+0.38

pH=14.38

0.060M NaOH

NaOH (0.060M) ------> Na+(0.060M) + OH-(0.060M)

[OH-]=0.060M

pOH=-Log[OH-]= -Log(0.060)= 1.22

pH + pOH = 14

pH=14- pOH= 14 - 1.22= 12.78

pH= 12.78

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