Question

a)What is the ionization energy (in kJ/mol) for the one-electron species, He+1 ? b)What is the...

a)What is the ionization energy (in kJ/mol) for the one-electron species, He+1 ?

b)What is the ionization energy (in kJ/mol) for the one-electron species, P+14 ?

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Answer #1

Both the given ions are single species electron containing ions. So by BOHR's formula we know :

E= -13.6z2/n2 ev

Since we have to calculate ionization energy, assuming the electrons in ground state n=1

a) For He+1, z=2 so E= -13.6*22 = 54.4 ev or 8.72 x 10-18 J

This is for one ion. For one mole it will be multiplied by avogadro number N = 6.62 x 1023

E = 5.77 x 106 KJ/mol

b) For P+14, z=15 so E = -13.6*152 = 3060 ev or 4.9 x 10-16 J

For one mole, E = 3.2 x 108 KJ/mol

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