Question

Beaker A contains 100.0 g of water initially at 10EC. Beaker B contains 100.0 g of water initially at 20°C. The contents of the two beakers are mixed. What is the final temperature of the contents? Assume that there are no heat losses and that the mass of the beakers is negligible. Useful data: The specific heat of water is 4.18 J/(g°C) Question 2 options: 15.0°C 17.5°C 12.5°C 10.0°C

Answer 1

heat lose by water                     heat gain by water

mct                          =         mct

100*4.18*20-t             =         100*4.18*(t-10)

20-t                         = t-10

20-t-t+10 =0

2t = 30

t = 30/2 = 15C⁰

final tempeature is 15C⁰ answer A