Consider the amino acid lysine (H3Lys2+ in the fully protonated form) which has pKa1 = 2.04, pKa2 = 9.08, and pKa3 = 10.69.
a. What is the charge on the principal species at pH 7.4 (blood)?
Circle one of +2 +1 0 -1 -2
b. What is the charge on the principal species at pH 10.0?
Circle one of +2 +1 0 -1 -2
c. Calculate the fraction of the total lysine which exists in the neutral form (HLys0) at pH 7.40.
Solution.
The structures of lysine at different pH are given below:
a. The pH=7.4 is between pKa1 and pKa2, it corresponds to the second form with a charge of (+1);
b. The pH=10.0 is between pKa2 and pKa3, it corresponds to the third form with a charge of (0);
c) At pH =7.4 the predominant forms of lysine are H2L and HL, which are related by Ka2:
Let's assume that solving a system of equation we can get the fraction of the total lysine which exists in the neutral form
or 2.06 %.
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