Question

A 8% acid solution is to be mixed with a 15% acid solution to produce 8 gallons of a 10% acid solution. How much of each is needed?

Answer 1

Let us denote by x, the amount of 8% solution. Since, we need to mix 8 gallons of a mixture, the amount of 15% solution must be 8-x.

Amount of solution of component1 = x

Percentage of solution of component1 = 8%

Amount of solution of component2 = 8-x

Percentage of solution of component1 = 15%

Amount of solution of mixture = 8 gallons

Percentage of solution of mixture = 10%

We obtain the equation by stating that the amount of solvent in the components must add up to the amount of solvant.

Therefore,

gallons ( of 8% solution)

2.28 gallons (of 15% solution)