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How could you use 1H NMR to determine the structure for compound C that has a...

How could you use 1H NMR to determine the structure for compound C that has a molecular formula of C6H4Cl2? Please explain, thanks.

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Answer #1

C6H4Cl2

DBE = Number of C - 1/2 Number of H - 1/2 Number of halogens + 1/2 Number of N +1

= 6 - 1/2 (4) - 1/2 (2) + 1/2 (0) + 1

= 6-2-1+1

= 4

The DBE = 4 means there is 3 pi bond or one ring with one double bond .

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