Consider the reaction
A+2B⇌C
whose rate at 25 ∘C was measured using three different sets of initial concentrations as listed in the following table:
Trial | [A] (M) |
[B] (M) |
Rate (M/s) |
1 | 0.15 | 0.010 | 2.7×10−4 |
2 | 0.15 | 0.020 | 5.4×10−4 |
3 | 0.30 | 0.010 |
1.1×10−3 |
Calculate the initial rate for the formation of C at 25 ∘C, if [A]=0.50M and [B]=0.075M.
Express your answer to two significant figures and include the appropriate units.
see experiment 1 and 3:
[A] doubles
[B] is constant
rate becomes 4 times
so, order of A is 2
see experiment 1 and 2:
[A] is constant
[B] doubles
rate doubles
so, order of B is 1
overall order = 2 + 1 = 3
Rate law is:
rate = k*[A]^2*[B]
Put values from 1st row of table in rate law
rate = k*[A]^2*[B]
2.7*10^-4 = k*0.15^2*0.01^1
k = 1.2 M-2.s-1
Now put all values to find rate at given concentration
rate = k*[A]^2*[B]
rate =1.2*0.5^2*0.075
rate = 0.0225 M/s
Answer: 2.2*10^-2 M/s
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