Question

if NO and NH3 are allowed to effuse through a porous membrane under identical conditions, the rate of effusion for NH3 will be _____ times that of NO.

Answer 1

We know that rate of effusion , r is inversely proportional square root of molar mass of the gas

(r_NH3 / r _NO )= (M _NO / M _NH3)

Where

r_NH3 = rate of NH₃ gas

r _NO = rate of NO gas

M _NO= Molar mass of NO= 30.01 g/mol

M _NH3 = Molar mass of NH₃= 17.031 g/mol

Plug the values we get

(r_NH3 / r _NO)= (30.01/17.031)

                   = 1.33

Therefore r_NH3 = 1.33 x r _NO

Therefore rate of effusion of NH₃ is 1.33 times that of NO