Question

Please answer these for me :)

Given numbers:

Mass of test tube: 13.180

Mass of copper oxide: 1.014

Mass of the test tube and copper metal: 14.028

1) Experimental Mass Percent (%) of Copper in the 1.014g Copper Oxide (3 SF)

2) Experimental Mass (g) of Oxygen in the 1.014g of Copper Oxide

3) Experimental Mass Percent (%) of Oxygen in the 1.014g Copper Oxide (3 SF)

4) Moles of Copper in the original 1.014g of Copper Oxide (3 SF)

5) Moles of Oxygen in the original g of Oxygen (3 SF)

6) Experimental Molar Ratio of Copper in CuxOy (3 SF)

7) Experimental Molar Ratio of Oxygen in CuxOy (3 SF)

8) Experimental Empirical Formula of Copper Oxide (enter ONLY WHOLE numbers - enter a 1 if needed)

Answer 1

1. Mass Percent (%) of Copper in the 1.014g Copper Oxide = (14.028-13.18)/1.014*100 = 83.63%

2. Mass (g) of Oxygen in the 1.014g of Copper Oxide = 1.014 - (14.028-13.18) = 0.166 g

3. Mass Percent (%) of Oxygen in the 1.014g Copper Oxide = 0.166/1.014*100 = 16.37%

4. Moles of Copper in the original 1.014g of Copper Oxide = w/mwt = (14.028-13.18)/63.55 = 0.0133 mole

5. Moles of Oxygen in the original 0.166g of Oxygen = 0.166/16 = 0.010375 mol

6,7. Experimental Molar Ratio of Copper in CuxOy

    Cu = 0.0133/0.010375 = 1.282

    O = 0.010375/0.010375 = 1

in simple whole number ratio

Cu = 1.282 = 1

O = 1

8. empirical formula = CuO