Question

Calculate the deltaH for: CuO (s) + CO (g) ---> Cu(s) + CO2(g) Given the following...

Calculate the deltaH for:
CuO (s) + CO (g) ---> Cu(s) + CO2(g)

Given the following thermochemical equations:

2CO (g) + O2(g) --> 2CO2 (g)
deltaH= -566.1kJ

2Cu (s) + O2(g) --> 2CuO(s)
deltaH= -310.5kJ

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Answer #1

2CO (g) + O2(g) --> 2CO2 (g)        deltaH= -566.1kJ

2Cu (s) + O2(g) --> 2CuO(s)          deltaH= -310.5kJ
(- )          ( -   )         (- )                            ( +)

---------------------------------------------------------------------------

2CO + 2CUO ------> 2Cu + 2Co2       delta H = -255.6Kj

divid by 2

CO + CUO -------> Cu + Co2             delta H = -255.6/2 = -127.8KJ

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