Calculate the value of the equilibrium constant, Kc, for the following reaction.
FeS(s) + 6CN-(aq) <-----> [Fe(CN)6]4-(aq) + S2-(aq) Kc=______?
The solubility product constant, Ksp, for FeS is 1.6 × 10^–19, and the formation constant, Kf, for [Fe(CN)6]^4– is 1.5 × 10^35
Kc=______
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